What are the solutions to the equation 3x-2x^2=1 ?

The solutions to the equation 3x-2x^2=1 are x= 1/2 ,x=1

Find the zeros of 3x-2x^2=1

The zeros of 3x-2x^2=1 are x= 1/2 ,x=1

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3 x - 2 x^{2} = 1

x = \frac{1}{2}, x = 1

Decimal Notation

x = 0.5, x = 1

Solution steps

3 x - 2 x^{2} = 1

Move

1

to the left side

3 x - 2 x^{2} - 1 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) ( - 1 )}{2 ( - 2 )}

3^{2} - 4 (- 2) (- 1) = 1

x_{1, 2} = \frac{- 3 \pm 1}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 1}{2 ( - 2 )}, x_{2} = \frac{- 3 - 1}{2 ( - 2 )}

x = \frac{- 3 + 1}{2 ( - 2 )} : \frac{1}{2}

x = \frac{- 3 - 1}{2 ( - 2 )} : 1

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 1

r^{2} = (60)^{2} + (- 11)^{2}

(k + 5)^{2} = 0

3 x^{2} - 8 x - 23 = - 4 x - 9

4 x^{2} + 6 x - 13 = 3 x^{2}

0 = 2 y - y^{2}

What are the solutions to the equation 3x-2x^2=1 ?
The solutions to the equation 3x-2x^2=1 are x= 1/2 ,x=1
Find the zeros of 3x-2x^2=1
The zeros of 3x-2x^2=1 are x= 1/2 ,x=1