What are the solutions to the equation 4x^2+6x-13=3x^2 ?

The solutions to the equation 4x^2+6x-13=3x^2 are x=-3+sqrt(22),x=-3-sqrt(22)

Find the zeros of 4x^2+6x-13=3x^2

The zeros of 4x^2+6x-13=3x^2 are x=-3+sqrt(22),x=-3-sqrt(22)

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4 x^{2} + 6 x - 13 = 3 x^{2}

x = - 3 + 22, x = - 3 - 22

Decimal Notation

x = 1.69041 \dots, x = - 7.69041 \dots

Solution steps

4 x^{2} + 6 x - 13 = 3 x^{2}

Move

3 x^{2}

to the left side

x^{2} + 6 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 13) = 222

x_{1, 2} = \frac{- 6 \pm 2 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 22}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 22}{2 \cdot 1}

x = \frac{- 6 + 2 22}{2 \cdot 1} : - 3 + 22

x = \frac{- 6 - 2 22}{2 \cdot 1} : - 3 - 22

The solutions to the quadratic equation are:

x = - 3 + 22, x = - 3 - 22

0 = 2 y - y^{2}

x, 0 = x^{2}

c^{2} = (x + 2)^{2} + (x + 2)^{2}

x^{2} + 4 x + 3 = 4

6 x^{2} = 2

What are the solutions to the equation 4x^2+6x-13=3x^2 ?
The solutions to the equation 4x^2+6x-13=3x^2 are x=-3+sqrt(22),x=-3-sqrt(22)
Find the zeros of 4x^2+6x-13=3x^2
The zeros of 4x^2+6x-13=3x^2 are x=-3+sqrt(22),x=-3-sqrt(22)