What are the solutions to the equation 10a^2+5a=15 ?

The solutions to the equation 10a^2+5a=15 are a=1,a=-3/2

Find the zeros of 10a^2+5a=15

The zeros of 10a^2+5a=15 are a=1,a=-3/2

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10 a^{2} + 5 a = 15

a = 1, a = - \frac{3}{2}

Decimal Notation

a = 1, a = - 1.5

Solution steps

10 a^{2} + 5 a = 15

Move

15

to the left side

10 a^{2} + 5 a - 15 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 10 ( - 15 )}{2 \cdot 10}

5^{2} - 4 \cdot 10 (- 15) = 25

a_{1, 2} = \frac{- 5 \pm 25}{2 \cdot 10}

Separate the solutions

a_{1} = \frac{- 5 + 25}{2 \cdot 10}, a_{2} = \frac{- 5 - 25}{2 \cdot 10}

a = \frac{- 5 + 25}{2 \cdot 10} : 1

a = \frac{- 5 - 25}{2 \cdot 10} : - \frac{3}{2}

The solutions to the quadratic equation are:

a = 1, a = - \frac{3}{2}

x^{2} - 4 x + 96 = 0

5 x = x^{2} + 1

16 t^{2} - 128 t + 192 = 0

12 y^{2} + 55 y + 63 = 0

6 a^{2} - 4 a - 22 = 0

What are the solutions to the equation 10a^2+5a=15 ?
The solutions to the equation 10a^2+5a=15 are a=1,a=-3/2
Find the zeros of 10a^2+5a=15
The zeros of 10a^2+5a=15 are a=1,a=-3/2