What are the solutions to the equation 9x^2+7x+49=0 ?

The solutions to the equation 9x^2+7x+49=0 are x=-7/18+i(7sqrt(35))/(18),x=-7/18-i(7sqrt(35))/(18)

Find the zeros of 9x^2+7x+49=0

The zeros of 9x^2+7x+49=0 are x=-7/18+i(7sqrt(35))/(18),x=-7/18-i(7sqrt(35))/(18)

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9 x^{2} + 7 x + 49 = 0

x = - \frac{7}{18} + i \frac{7 35}{18}, x = - \frac{7}{18} - i \frac{7 35}{18}

Solution steps

9 x^{2} + 7 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 9 \cdot 49}{2 \cdot 9}

Simplify

7^{2} - 4 \cdot 9 \cdot 49 : 735 i

x_{1, 2} = \frac{- 7 \pm 7 35 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 7 + 7 35 i}{2 \cdot 9}, x_{2} = \frac{- 7 - 7 35 i}{2 \cdot 9}

x = \frac{- 7 + 7 35 i}{2 \cdot 9} : - \frac{7}{18} + i \frac{7 35}{18}

x = \frac{- 7 - 7 35 i}{2 \cdot 9} : - \frac{7}{18} - i \frac{7 35}{18}

The solutions to the quadratic equation are:

x = - \frac{7}{18} + i \frac{7 35}{18}, x = - \frac{7}{18} - i \frac{7 35}{18}

13 x - 3 x^{2} = 0

x^{2} = 242

15 x - 10 = 6 x - (x x^{2}) + (- x + 3)

13 x^{2} - 16 x = 4

(2 x - 1) (x - 2) = 5

What are the solutions to the equation 9x^2+7x+49=0 ?
The solutions to the equation 9x^2+7x+49=0 are x=-7/18+i(7sqrt(35))/(18),x=-7/18-i(7sqrt(35))/(18)
Find the zeros of 9x^2+7x+49=0
The zeros of 9x^2+7x+49=0 are x=-7/18+i(7sqrt(35))/(18),x=-7/18-i(7sqrt(35))/(18)