What are the solutions to the equation 13x^2-16x=4 ?

The solutions to the equation 13x^2-16x=4 are x=(2(4+sqrt(29)))/(13),x=(2(4-sqrt(29)))/(13)

Find the zeros of 13x^2-16x=4

The zeros of 13x^2-16x=4 are x=(2(4+sqrt(29)))/(13),x=(2(4-sqrt(29)))/(13)

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13 x^{2} - 16 x = 4

x = \frac{2 ( 4 + 29 )}{13}, x = \frac{2 ( 4 - 29 )}{13}

Decimal Notation

x = 1.44387 \dots, x = - 0.21310 \dots

Solution steps

13 x^{2} - 16 x = 4

Move

4

to the left side

13 x^{2} - 16 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 13 ( - 4 )}{2 \cdot 13}

(- 16)^{2} - 4 \cdot 13 (- 4) = 429

x_{1, 2} = \frac{- ( - 16 ) \pm 4 29}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 29}{2 \cdot 13}, x_{2} = \frac{- ( - 16 ) - 4 29}{2 \cdot 13}

x = \frac{- ( - 16 ) + 4 29}{2 \cdot 13} : \frac{2 ( 4 + 29 )}{13}

x = \frac{- ( - 16 ) - 4 29}{2 \cdot 13} : \frac{2 ( 4 - 29 )}{13}

The solutions to the quadratic equation are:

x = \frac{2 ( 4 + 29 )}{13}, x = \frac{2 ( 4 - 29 )}{13}

(2 x - 1) (x - 2) = 5

- 5 x^{2} + 9 = 0

- 8 x^{2} + 2 x + 10

a^{2} + 3. 4^{2} = 5. 6^{2}

6 t^{2} + 36 = 0

What are the solutions to the equation 13x^2-16x=4 ?
The solutions to the equation 13x^2-16x=4 are x=(2(4+sqrt(29)))/(13),x=(2(4-sqrt(29)))/(13)
Find the zeros of 13x^2-16x=4
The zeros of 13x^2-16x=4 are x=(2(4+sqrt(29)))/(13),x=(2(4-sqrt(29)))/(13)