What are the solutions to the equation n^2-10n+29=0 ?

The solutions to the equation n^2-10n+29=0 are n=5+2i,n=5-2i

Find the zeros of n^2-10n+29=0

The zeros of n^2-10n+29=0 are n=5+2i,n=5-2i

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n^{2} - 10 n + 29 = 0

n = 5 + 2 i, n = 5 - 2 i

Solution steps

n^{2} - 10 n + 29 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 29}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 29 : 4 i

n_{1, 2} = \frac{- ( - 10 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 10 ) + 4 i}{2 \cdot 1}, n_{2} = \frac{- ( - 10 ) - 4 i}{2 \cdot 1}

n = \frac{- ( - 10 ) + 4 i}{2 \cdot 1} : 5 + 2 i

n = \frac{- ( - 10 ) - 4 i}{2 \cdot 1} : 5 - 2 i

The solutions to the quadratic equation are:

n = 5 + 2 i, n = 5 - 2 i

x^{2} = n

5 x^{2} + 4 x - 8 = 0

3 x^{2} - x

3 x^{2} + 35 = 24 x - 1

15 x^{2} - 13 x - 6 = 0

What are the solutions to the equation n^2-10n+29=0 ?
The solutions to the equation n^2-10n+29=0 are n=5+2i,n=5-2i
Find the zeros of n^2-10n+29=0
The zeros of n^2-10n+29=0 are n=5+2i,n=5-2i