What are the solutions to the equation (2y+8)^2=125 ?

The solutions to the equation (2y+8)^2=125 are y=(5sqrt(5)-8)/2 ,y=(-5sqrt(5)-8)/2

Find the zeros of (2y+8)^2=125

The zeros of (2y+8)^2=125 are y=(5sqrt(5)-8)/2 ,y=(-5sqrt(5)-8)/2

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(2 y + 8)^{2} = 125

y = \frac{5 5 - 8}{2}, y = \frac{- 5 5 - 8}{2}

Decimal Notation

y = 1.59016 \dots, y = - 9.59016 \dots

Solution steps

(2 y + 8)^{2} = 125

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 y + 8 = 125 : y = \frac{5 5 - 8}{2}

Solve

2 y + 8 = - 125 : y = \frac{- 5 5 - 8}{2}

The solutions to the quadratic equation are:

y = \frac{5 5 - 8}{2}, y = \frac{- 5 5 - 8}{2}

\frac{1}{2} (15 \cdot 1 0^{- 6}) (11 \cdot 1 0^{3})

- \frac{π}{2} < 4 x + π < \frac{π}{2}

4 x^{2} - 26 x + 30

a^{2} + 10 a + 16

2 x^{2} - 5 x = 9

What are the solutions to the equation (2y+8)^2=125 ?
The solutions to the equation (2y+8)^2=125 are y=(5sqrt(5)-8)/2 ,y=(-5sqrt(5)-8)/2
Find the zeros of (2y+8)^2=125
The zeros of (2y+8)^2=125 are y=(5sqrt(5)-8)/2 ,y=(-5sqrt(5)-8)/2