What are the solutions to the equation solvefor x,(x+y)^2-1=0 ?

The solutions to the equation solvefor x,(x+y)^2-1=0 are x=1-y,x=-1-y

Find the zeros of solvefor x,(x+y)^2-1=0

The zeros of solvefor x,(x+y)^2-1=0 are x=1-y,x=-1-y

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solve for

x, (x + y)^{2} - 1 = 0

x = 1 - y, x = - 1 - y

Solution steps

(x + y)^{2} - 1 = 0

Move

1

to the right side

(x + y)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + y = 1 : x = 1 - y

Solve

x + y = - 1 : x = - 1 - y

The solutions to the quadratic equation are:

x = 1 - y, x = - 1 - y

x, x^{2} - k x + 1681 = 0 s

(2 x + 3) \cdot (3 x - 1) = - 4

(5 w - 1) (w + 3) = 0

2 x^{2} + 6 x + 2 = 4

5 x^{2} + 10 = 9

What are the solutions to the equation solvefor x,(x+y)^2-1=0 ?
The solutions to the equation solvefor x,(x+y)^2-1=0 are x=1-y,x=-1-y
Find the zeros of solvefor x,(x+y)^2-1=0
The zeros of solvefor x,(x+y)^2-1=0 are x=1-y,x=-1-y