What are the solutions to the equation (5w-1)(w+3)=0 ?

The solutions to the equation (5w-1)(w+3)=0 are w= 1/5 ,w=-3

Find the zeros of (5w-1)(w+3)=0

The zeros of (5w-1)(w+3)=0 are w= 1/5 ,w=-3

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(5 w - 1) (w + 3) = 0

w = \frac{1}{5}, w = - 3

Decimal Notation

w = 0.2, w = - 3

Solution steps

(5 w - 1) (w + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 w - 1 = 0 or w + 3 = 0

Solve

5 w - 1 = 0 : w = \frac{1}{5}

Solve

w + 3 = 0 : w = - 3

The solutions to the quadratic equation are:

w = \frac{1}{5}, w = - 3

2 x^{2} + 6 x + 2 = 4

5 x^{2} + 10 = 9

2 n^{2} + 2 n^{2} = 1

(x + 2)^{2} = 2 x (x + 2) + 12

x (x + 4) = 15 - 6

What are the solutions to the equation (5w-1)(w+3)=0 ?
The solutions to the equation (5w-1)(w+3)=0 are w= 1/5 ,w=-3
Find the zeros of (5w-1)(w+3)=0
The zeros of (5w-1)(w+3)=0 are w= 1/5 ,w=-3