What are the solutions to the equation 2n^2+2n^2=1 ?

The solutions to the equation 2n^2+2n^2=1 are n= 1/2 ,n=-1/2

Find the zeros of 2n^2+2n^2=1

The zeros of 2n^2+2n^2=1 are n= 1/2 ,n=-1/2

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2 n^{2} + 2 n^{2} = 1

n = \frac{1}{2}, n = - \frac{1}{2}

Decimal Notation

n = 0.5, n = - 0.5

Solution steps

2 n^{2} + 2 n^{2} = 1

Add similar elements:

2 n^{2} + 2 n^{2} = 4 n^{2}

4 n^{2} = 1

Divide both sides by

4

n^{2} = \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{1}{4}, n = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

n = \frac{1}{2}, n = - \frac{1}{2}

(x + 2)^{2} = 2 x (x + 2) + 12

x (x + 4) = 15 - 6

3 x^{2} + 4 x - 7 = 0

x^{2} - 4 x + 16 = 18

2 x^{2} - 17 x + 16 = 0

What are the solutions to the equation 2n^2+2n^2=1 ?
The solutions to the equation 2n^2+2n^2=1 are n= 1/2 ,n=-1/2
Find the zeros of 2n^2+2n^2=1
The zeros of 2n^2+2n^2=1 are n= 1/2 ,n=-1/2