What are the solutions to the equation factor 3x^2+4x-7=0 ?

The solutions to the equation factor 3x^2+4x-7=0 are x=1,x=-7/3

Find the zeros of factor 3x^2+4x-7=0

The zeros of factor 3x^2+4x-7=0 are x=1,x=-7/3

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3 x^{2} + 4 x - 7 = 0

x = 1, x = - \frac{7}{3}

Decimal Notation

x = 1, x = - 2.33333 \dots

Solution steps

3 x^{2} + 4 x - 7 = 0

Factor

3 x^{2} + 4 x - 7 : (x - 1) (3 x + 7)

(x - 1) (3 x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 3 x + 7 = 0

Solve

x - 1 = 0 : x = 1

Solve

3 x + 7 = 0 : x = - \frac{7}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{7}{3}

x^{2} - 4 x + 16 = 18

2 x^{2} - 17 x + 16 = 0

(- a)^{2} - 4 (1) (- 2 a) = 0

v, v^{2} = u^{2} + 2 a s

x, (x - 0)^{2} = 4 p (y - 10)

What are the solutions to the equation factor 3x^2+4x-7=0 ?
The solutions to the equation factor 3x^2+4x-7=0 are x=1,x=-7/3
Find the zeros of factor 3x^2+4x-7=0
The zeros of factor 3x^2+4x-7=0 are x=1,x=-7/3