What are the solutions to the equation 14z^2-51z=54 ?

The solutions to the equation 14z^2-51z=54 are z= 9/2 ,z=-6/7

Find the zeros of 14z^2-51z=54

The zeros of 14z^2-51z=54 are z= 9/2 ,z=-6/7

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14 z^{2} - 51 z = 54

z = \frac{9}{2}, z = - \frac{6}{7}

Decimal Notation

z = 4.5, z = - 0.85714 \dots

Solution steps

14 z^{2} - 51 z = 54

Move

54

to the left side

14 z^{2} - 51 z - 54 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 51 ) \pm ( - 51 ) ^{2} - 4 \cdot 14 ( - 54 )}{2 \cdot 14}

(- 51)^{2} - 4 \cdot 14 (- 54) = 75

z_{1, 2} = \frac{- ( - 51 ) \pm 75}{2 \cdot 14}

Separate the solutions

z_{1} = \frac{- ( - 51 ) + 75}{2 \cdot 14}, z_{2} = \frac{- ( - 51 ) - 75}{2 \cdot 14}

z = \frac{- ( - 51 ) + 75}{2 \cdot 14} : \frac{9}{2}

z = \frac{- ( - 51 ) - 75}{2 \cdot 14} : - \frac{6}{7}

The solutions to the quadratic equation are:

z = \frac{9}{2}, z = - \frac{6}{7}

y^{2} - 6 y + 12 = 0

4 y^{2} - (4 - y^{2}) = 4

x^{2} - 0.011 x - 0.063 = 0

3 x^{2} + 9 x = - 6

c^{2} + 12 c + 36 = 121

What are the solutions to the equation 14z^2-51z=54 ?
The solutions to the equation 14z^2-51z=54 are z= 9/2 ,z=-6/7
Find the zeros of 14z^2-51z=54
The zeros of 14z^2-51z=54 are z= 9/2 ,z=-6/7