What are the solutions to the equation -4=x^2+5x ?

The solutions to the equation -4=x^2+5x are x=-1,x=-4

Find the zeros of -4=x^2+5x

The zeros of -4=x^2+5x are x=-1,x=-4

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- 4 = x^{2} + 5 x

x = - 1, x = - 4

Solution steps

- 4 = x^{2} + 5 x

Switch sides

x^{2} + 5 x = - 4

Move

4

to the left side

x^{2} + 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 \cdot 1}, x_{2} = \frac{- 5 - 3}{2 \cdot 1}

x = \frac{- 5 + 3}{2 \cdot 1} : - 1

x = \frac{- 5 - 3}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 1, x = - 4

x^{2} + 10 x = - 9

4 k^{2} - 2 = - 15

22 - 22 x = (5 x + 3) (x - 1)

- 4 n^{2} = 6 n + 16 - 5 n^{2}

w^{2} - w - 12 = 0

What are the solutions to the equation -4=x^2+5x ?
The solutions to the equation -4=x^2+5x are x=-1,x=-4
Find the zeros of -4=x^2+5x
The zeros of -4=x^2+5x are x=-1,x=-4