What are the solutions to the equation 15x^2+43x+8=0 ?

The solutions to the equation 15x^2+43x+8=0 are x=-1/5 ,x=-8/3

Find the zeros of 15x^2+43x+8=0

The zeros of 15x^2+43x+8=0 are x=-1/5 ,x=-8/3

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15 x^{2} + 43 x + 8 = 0

x = - \frac{1}{5}, x = - \frac{8}{3}

Decimal Notation

x = - 0.2, x = - 2.66666 \dots

Solution steps

15 x^{2} + 43 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 43 \pm 4 3 ^{2} - 4 \cdot 15 \cdot 8}{2 \cdot 15}

4 3^{2} - 4 \cdot 15 \cdot 8 = 37

x_{1, 2} = \frac{- 43 \pm 37}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 43 + 37}{2 \cdot 15}, x_{2} = \frac{- 43 - 37}{2 \cdot 15}

x = \frac{- 43 + 37}{2 \cdot 15} : - \frac{1}{5}

x = \frac{- 43 - 37}{2 \cdot 15} : - \frac{8}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = - \frac{8}{3}

(y - 2) (3 y + 5) = y (y - 2)

12 n^{2} - 18 n = 0

(2 - x) (3 - x) - 1 = 0

4 (x + 5) (4 + x) = 34

6 y^{2} - 216 = 0

What are the solutions to the equation 15x^2+43x+8=0 ?
The solutions to the equation 15x^2+43x+8=0 are x=-1/5 ,x=-8/3
Find the zeros of 15x^2+43x+8=0
The zeros of 15x^2+43x+8=0 are x=-1/5 ,x=-8/3