What are the solutions to the equation 4(x+5)(4+x)=34 ?

The solutions to the equation 4(x+5)(4+x)=34 are x=(-9+sqrt(35))/2 ,x=-(9+sqrt(35))/2

Find the zeros of 4(x+5)(4+x)=34

The zeros of 4(x+5)(4+x)=34 are x=(-9+sqrt(35))/2 ,x=-(9+sqrt(35))/2

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4 (x + 5) (4 + x) = 34

x = \frac{- 9 + 35}{2}, x = - \frac{9 + 35}{2}

Decimal Notation

x = - 1.54196 \dots, x = - 7.45803 \dots

Solution steps

4 (x + 5) (4 + x) = 34

Expand

4 (x + 5) (4 + x) : 36 x + 4 x^{2} + 80

36 x + 4 x^{2} + 80 = 34

Move

34

to the left side

4 x^{2} + 36 x + 46 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 4 \cdot 46}{2 \cdot 4}

3 6^{2} - 4 \cdot 4 \cdot 46 = 435

x_{1, 2} = \frac{- 36 \pm 4 35}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 36 + 4 35}{2 \cdot 4}, x_{2} = \frac{- 36 - 4 35}{2 \cdot 4}

x = \frac{- 36 + 4 35}{2 \cdot 4} : \frac{- 9 + 35}{2}

x = \frac{- 36 - 4 35}{2 \cdot 4} : - \frac{9 + 35}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 35}{2}, x = - \frac{9 + 35}{2}

6 y^{2} - 216 = 0

11 y + 2 y^{2} - 21 = 0

x^{2} - 15 x + 100 = 0

26 x^{2} - 104 x = 0

y, x + (y - 5)^{2} = 0

What are the solutions to the equation 4(x+5)(4+x)=34 ?
The solutions to the equation 4(x+5)(4+x)=34 are x=(-9+sqrt(35))/2 ,x=-(9+sqrt(35))/2
Find the zeros of 4(x+5)(4+x)=34
The zeros of 4(x+5)(4+x)=34 are x=(-9+sqrt(35))/2 ,x=-(9+sqrt(35))/2