What are the solutions to the equation 11y+2y^2-21=0 ?

The solutions to the equation 11y+2y^2-21=0 are y= 3/2 ,y=-7

Find the zeros of 11y+2y^2-21=0

The zeros of 11y+2y^2-21=0 are y= 3/2 ,y=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

11 y + 2 y^{2} - 21 = 0

y = \frac{3}{2}, y = - 7

Decimal Notation

y = 1.5, y = - 7

Solution steps

11 y + 2 y^{2} - 21 = 0

Write in the standard form

a x^{2} + b x + c = 0

2 y^{2} + 11 y - 21 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 ( - 21 )}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 (- 21) = 17

y_{1, 2} = \frac{- 11 \pm 17}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- 11 + 17}{2 \cdot 2}, y_{2} = \frac{- 11 - 17}{2 \cdot 2}

y = \frac{- 11 + 17}{2 \cdot 2} : \frac{3}{2}

y = \frac{- 11 - 17}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

y = \frac{3}{2}, y = - 7

x^{2} - 15 x + 100 = 0

26 x^{2} - 104 x = 0

y, x + (y - 5)^{2} = 0

x, x^{2} + y^{2} = Z^{2}

4 a^{2} - 4 a - 8 = 0

What are the solutions to the equation 11y+2y^2-21=0 ?
The solutions to the equation 11y+2y^2-21=0 are y= 3/2 ,y=-7
Find the zeros of 11y+2y^2-21=0
The zeros of 11y+2y^2-21=0 are y= 3/2 ,y=-7