What are the solutions to the equation 26x^2-104x=0 ?

The solutions to the equation 26x^2-104x=0 are x=4,x=0

Find the zeros of 26x^2-104x=0

The zeros of 26x^2-104x=0 are x=4,x=0

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26 x^{2} - 104 x = 0

x = 4, x = 0

Solution steps

26 x^{2} - 104 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 104 ) \pm ( - 104 ) ^{2} - 4 \cdot 26 \cdot 0}{2 \cdot 26}

(- 104)^{2} - 4 \cdot 26 \cdot 0 = 104

x_{1, 2} = \frac{- ( - 104 ) \pm 104}{2 \cdot 26}

Separate the solutions

x_{1} = \frac{- ( - 104 ) + 104}{2 \cdot 26}, x_{2} = \frac{- ( - 104 ) - 104}{2 \cdot 26}

x = \frac{- ( - 104 ) + 104}{2 \cdot 26} : 4

x = \frac{- ( - 104 ) - 104}{2 \cdot 26} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

y, x + (y - 5)^{2} = 0

x, x^{2} + y^{2} = Z^{2}

4 a^{2} - 4 a - 8 = 0

- x^{2} + 15 x - 50 = 0

- 4 x^{2} + 11 x - 275 = 0

What are the solutions to the equation 26x^2-104x=0 ?
The solutions to the equation 26x^2-104x=0 are x=4,x=0
Find the zeros of 26x^2-104x=0
The zeros of 26x^2-104x=0 are x=4,x=0