What are the solutions to the equation 3x^2+12x-24=0 ?

The solutions to the equation 3x^2+12x-24=0 are x=2(sqrt(3)-1),x=-2(1+sqrt(3))

Find the zeros of 3x^2+12x-24=0

The zeros of 3x^2+12x-24=0 are x=2(sqrt(3)-1),x=-2(1+sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 12 x - 24 = 0

x = 2 (3 - 1), x = - 2 (1 + 3)

Decimal Notation

x = 1.46410 \dots, x = - 5.46410 \dots

Solution steps

3 x^{2} + 12 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 ( - 24 )}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 (- 24) = 123

x_{1, 2} = \frac{- 12 \pm 12 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 12 3}{2 \cdot 3}, x_{2} = \frac{- 12 - 12 3}{2 \cdot 3}

x = \frac{- 12 + 12 3}{2 \cdot 3} : 2 (3 - 1)

x = \frac{- 12 - 12 3}{2 \cdot 3} : - 2 (1 + 3)

The solutions to the quadratic equation are:

x = 2 (3 - 1), x = - 2 (1 + 3)

- 5 x^{2} - 9 x + 4 = 0

4 t^{2} + 12 t - 17 = 0

x^{2} - 9 = 0

2 s^{2} - 50 = 0

5 x^{2} - 6 x = 8

What are the solutions to the equation 3x^2+12x-24=0 ?
The solutions to the equation 3x^2+12x-24=0 are x=2(sqrt(3)-1),x=-2(1+sqrt(3))
Find the zeros of 3x^2+12x-24=0
The zeros of 3x^2+12x-24=0 are x=2(sqrt(3)-1),x=-2(1+sqrt(3))