What are the solutions to the equation 3(4x+3)^2=48 ?

The solutions to the equation 3(4x+3)^2=48 are x= 1/4 ,x=-7/4

Find the zeros of 3(4x+3)^2=48

The zeros of 3(4x+3)^2=48 are x= 1/4 ,x=-7/4

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3 (4 x + 3)^{2} = 48

x = \frac{1}{4}, x = - \frac{7}{4}

Decimal Notation

x = 0.25, x = - 1.75

Solution steps

3 (4 x + 3)^{2} = 48

Divide both sides by

3

(4 x + 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 3 = 16 : x = \frac{1}{4}

Solve

4 x + 3 = - 16 : x = - \frac{7}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{7}{4}

- 3 x^{2} + 40 x + 75 = 0

7 x^{2} - 3 x + 8 = 9 x^{2} + 15

15 x + x^{2} = 0

5 x^{2} - 12 a x + 3 a^{2} = 0

(\frac{2}{3} y - 24) (y - 36) = 240

What are the solutions to the equation 3(4x+3)^2=48 ?
The solutions to the equation 3(4x+3)^2=48 are x= 1/4 ,x=-7/4
Find the zeros of 3(4x+3)^2=48
The zeros of 3(4x+3)^2=48 are x= 1/4 ,x=-7/4