What are the solutions to the equation 5x^2-12ax+3a^2=0 ?

The solutions to the equation 5x^2-12ax+3a^2=0 are x=((6+sqrt(21))a)/5 ,x=((6-sqrt(21))a)/5

Find the zeros of 5x^2-12ax+3a^2=0

The zeros of 5x^2-12ax+3a^2=0 are x=((6+sqrt(21))a)/5 ,x=((6-sqrt(21))a)/5

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5 x^{2} - 12 a x + 3 a^{2} = 0

x = \frac{( 6 + 21 ) a}{5}, x = \frac{( 6 - 21 ) a}{5}

Solution steps

5 x^{2} - 12 a x + 3 a^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 a ) \pm ( - 12 a ) ^{2} - 4 \cdot 5 \cdot 3 a ^{2}}{2 \cdot 5}

Simplify

(- 12 a)^{2} - 4 \cdot 5 \cdot 3 a^{2} : 221 a

x_{1, 2} = \frac{- ( - 12 a ) \pm 2 21 a}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 12 a ) + 2 21 a}{2 \cdot 5}, x_{2} = \frac{- ( - 12 a ) - 2 21 a}{2 \cdot 5}

x = \frac{- ( - 12 a ) + 2 21 a}{2 \cdot 5} : \frac{( 6 + 21 ) a}{5}

x = \frac{- ( - 12 a ) - 2 21 a}{2 \cdot 5} : \frac{( 6 - 21 ) a}{5}

The solutions to the quadratic equation are:

x = \frac{( 6 + 21 ) a}{5}, x = \frac{( 6 - 21 ) a}{5}

(\frac{2}{3} y - 24) (y - 36) = 240

81 - x^{2} = - 9

(x + 3)^{2} + (x + 2) (x - 2) = x (x - 1) - 5

u^{2} - 25 u + 144 = 0

x^{2} = 4 x + 32

What are the solutions to the equation 5x^2-12ax+3a^2=0 ?
The solutions to the equation 5x^2-12ax+3a^2=0 are x=((6+sqrt(21))a)/5 ,x=((6-sqrt(21))a)/5
Find the zeros of 5x^2-12ax+3a^2=0
The zeros of 5x^2-12ax+3a^2=0 are x=((6+sqrt(21))a)/5 ,x=((6-sqrt(21))a)/5