What are the solutions to the equation u^2-25u+144=0 ?

The solutions to the equation u^2-25u+144=0 are u=16,u=9

Find the zeros of u^2-25u+144=0

The zeros of u^2-25u+144=0 are u=16,u=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

u^{2} - 25 u + 144 = 0

u = 16, u = 9

Solution steps

u^{2} - 25 u + 144 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 1 \cdot 144}{2 \cdot 1}

(- 25)^{2} - 4 \cdot 1 \cdot 144 = 7

u_{1, 2} = \frac{- ( - 25 ) \pm 7}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 25 ) + 7}{2 \cdot 1}, u_{2} = \frac{- ( - 25 ) - 7}{2 \cdot 1}

u = \frac{- ( - 25 ) + 7}{2 \cdot 1} : 16

u = \frac{- ( - 25 ) - 7}{2 \cdot 1} : 9

The solutions to the quadratic equation are:

u = 16, u = 9

x^{2} = 4 x + 32

x^{2} - 1 = 0

x, f = x^{2} - h^{2}

3 x^{2} = 13 x - 10

4 - 3 x - x^{2}

What are the solutions to the equation u^2-25u+144=0 ?
The solutions to the equation u^2-25u+144=0 are u=16,u=9
Find the zeros of u^2-25u+144=0
The zeros of u^2-25u+144=0 are u=16,u=9