What are the solutions to the equation x^2= 2/5 ?

The solutions to the equation x^2= 2/5 are x=sqrt(2/5),x=-sqrt(2/5)

Find the zeros of x^2= 2/5

The zeros of x^2= 2/5 are x=sqrt(2/5),x=-sqrt(2/5)

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x^{2} = \frac{2}{5}

x = \frac{2}{5}, x = - \frac{2}{5}

Decimal Notation

x = 0.63245 \dots, x = - 0.63245 \dots

Solution steps

x^{2} = \frac{2}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{2}{5}, x = - \frac{2}{5}

3 x^{2} + 16 x + 1 = 0

200 = 0.04 t^{2} + 2 t

3 x + 1 = - x^{2}

(- 1 - 7 + 2 x)^{2} + (4 - x)^{2} = 45

1 1^{2} + x^{2} = 1 4^{2}

What are the solutions to the equation x^2= 2/5 ?
The solutions to the equation x^2= 2/5 are x=sqrt(2/5),x=-sqrt(2/5)
Find the zeros of x^2= 2/5
The zeros of x^2= 2/5 are x=sqrt(2/5),x=-sqrt(2/5)