What are the solutions to the equation 200=0.04t^2+2t ?

The solutions to the equation 200=0.04t^2+2t are t=50,t=-100

Find the zeros of 200=0.04t^2+2t

The zeros of 200=0.04t^2+2t are t=50,t=-100

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200 = 0.04 t^{2} + 2 t

t = 50, t = - 100

Solution steps

200 = 0.04 t^{2} + 2 t

Multiply both sides by

100

20000 = 4 t^{2} + 200 t

Switch sides

4 t^{2} + 200 t = 20000

Move

20000

to the left side

4 t^{2} + 200 t - 20000 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 200 \pm 20 0 ^{2} - 4 \cdot 4 ( - 20000 )}{2 \cdot 4}

20 0^{2} - 4 \cdot 4 (- 20000) = 600

t_{1, 2} = \frac{- 200 \pm 600}{2 \cdot 4}

Separate the solutions

t_{1} = \frac{- 200 + 600}{2 \cdot 4}, t_{2} = \frac{- 200 - 600}{2 \cdot 4}

t = \frac{- 200 + 600}{2 \cdot 4} : 50

t = \frac{- 200 - 600}{2 \cdot 4} : - 100

The solutions to the quadratic equation are:

t = 50, t = - 100

3 x + 1 = - x^{2}

(- 1 - 7 + 2 x)^{2} + (4 - x)^{2} = 45

1 1^{2} + x^{2} = 1 4^{2}

(2 x + 3) (2 x - 3) = 4 (2 x + 3)

3 + 5 x = - 9 x^{2}

What are the solutions to the equation 200=0.04t^2+2t ?
The solutions to the equation 200=0.04t^2+2t are t=50,t=-100
Find the zeros of 200=0.04t^2+2t
The zeros of 200=0.04t^2+2t are t=50,t=-100