What are the solutions to the equation 2x^2-4x=-6 ?

The solutions to the equation 2x^2-4x=-6 are x=1+sqrt(2)i,x=1-sqrt(2)i

Find the zeros of 2x^2-4x=-6

The zeros of 2x^2-4x=-6 are x=1+sqrt(2)i,x=1-sqrt(2)i

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2 x^{2} - 4 x = - 6

x = 1 + 2 i, x = 1 - 2 i

Solution steps

2 x^{2} - 4 x = - 6

Move

6

to the left side

2 x^{2} - 4 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

(- 4)^{2} - 4 \cdot 2 \cdot 6 : 42 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 2}

x = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 2} : 1 + 2 i

x = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 2} : 1 - 2 i

The solutions to the quadratic equation are:

x = 1 + 2 i, x = 1 - 2 i

(2 s - 1)^{2} - 255 = 0

13 x^{2} - x = 0

(r - 4) (r + 8) = - 24

l^{2} - 5 l - 36 = 0

12 x^{2} + 163 x + 15 = 0

What are the solutions to the equation 2x^2-4x=-6 ?
The solutions to the equation 2x^2-4x=-6 are x=1+sqrt(2)i,x=1-sqrt(2)i
Find the zeros of 2x^2-4x=-6
The zeros of 2x^2-4x=-6 are x=1+sqrt(2)i,x=1-sqrt(2)i