What are the solutions to the equation (3x+6)^2-18=0 ?

The solutions to the equation (3x+6)^2-18=0 are x=sqrt(2)-2,x=-2-sqrt(2)

Find the zeros of (3x+6)^2-18=0

The zeros of (3x+6)^2-18=0 are x=sqrt(2)-2,x=-2-sqrt(2)

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(3 x + 6)^{2} - 18 = 0

x = 2 - 2, x = - 2 - 2

Decimal Notation

x = - 0.58578 \dots, x = - 3.41421 \dots

Solution steps

(3 x + 6)^{2} - 18 = 0

Move

18

to the right side

(3 x + 6)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 6 = 18 : x = 2 - 2

Solve

3 x + 6 = - 18 : x = - 2 - 2

The solutions to the quadratic equation are:

x = 2 - 2, x = - 2 - 2

x, 2 x^{2} - 3 x - 14 = 0

y^{2} = - 5 y + 5

x - 1 = 1 - 2 x + x^{2}

5 u^{2} - 29 u - 6 = 0

2 k^{2} + 6 k = 36

What are the solutions to the equation (3x+6)^2-18=0 ?
The solutions to the equation (3x+6)^2-18=0 are x=sqrt(2)-2,x=-2-sqrt(2)
Find the zeros of (3x+6)^2-18=0
The zeros of (3x+6)^2-18=0 are x=sqrt(2)-2,x=-2-sqrt(2)