What are the solutions to the equation z(z+5)=-6 ?

The solutions to the equation z(z+5)=-6 are z=-2,z=-3

Find the zeros of z(z+5)=-6

The zeros of z(z+5)=-6 are z=-2,z=-3

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z (z + 5) = - 6

z = - 2, z = - 3

Solution steps

z (z + 5) = - 6

Expand

z (z + 5) : z^{2} + 5 z

z^{2} + 5 z = - 6

Move

6

to the left side

z^{2} + 5 z + 6 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

z_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 5 + 1}{2 \cdot 1}, z_{2} = \frac{- 5 - 1}{2 \cdot 1}

z = \frac{- 5 + 1}{2 \cdot 1} : - 2

z = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

z = - 2, z = - 3

0 = \frac{- 1}{500} (x - 100)^{2} + 20

5 x^{2} + 2 = 37

a^{2} + 3 a - 1 = 0

3 w^{2} - 4 w - 55 = 0

2 x^{2} - 7 = - 39

What are the solutions to the equation z(z+5)=-6 ?
The solutions to the equation z(z+5)=-6 are z=-2,z=-3
Find the zeros of z(z+5)=-6
The zeros of z(z+5)=-6 are z=-2,z=-3