What are the solutions to the equation x^2=24-5x ?

The solutions to the equation x^2=24-5x are x=3,x=-8

Find the zeros of x^2=24-5x

The zeros of x^2=24-5x are x=3,x=-8

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x^{2} = 24 - 5 x

x = 3, x = - 8

Solution steps

x^{2} = 24 - 5 x

Move

5 x

to the left side

x^{2} + 5 x = 24

Move

24

to the left side

x^{2} + 5 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 24) = 11

x_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 11}{2 \cdot 1}, x_{2} = \frac{- 5 - 11}{2 \cdot 1}

x = \frac{- 5 + 11}{2 \cdot 1} : 3

x = \frac{- 5 - 11}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 3, x = - 8

0 = \frac{12 - x ^{2}}{8}

- 6 x^{2} + 3 x = 0

6 x^{2} - 54 x + 36 = 0

b^{2} - 2 b - 15 = 0

x, s (x) = x^{2} - 6 x + 5

What are the solutions to the equation x^2=24-5x ?
The solutions to the equation x^2=24-5x are x=3,x=-8
Find the zeros of x^2=24-5x
The zeros of x^2=24-5x are x=3,x=-8