What are the solutions to the equation t^2=4t-4 ?

The solutions to the equation t^2=4t-4 are t=2

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t^2=4t-4

t^{2} = 4 t - 4

t = 2

Solution steps

t^{2} = 4 t - 4

Move

4

to the left side

t^{2} + 4 = 4 t

Move

4 t

to the left side

t^{2} + 4 - 4 t = 0

Write in the standard form

a x^{2} + b x + c = 0

t^{2} - 4 t + 4 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

t_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

t = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

t = 2

The solution to the quadratic equation is:

t = 2

x^{2} - x - 3 = 0

3 x^{2} - 18 = 2 x + 1

m^{2} + 12 m + 20 = 0

- 3 x^{2} - 120 = 0

4 x^{2} + 3 x - 22 = 0

What are the solutions to the equation t^2=4t-4 ?
The solutions to the equation t^2=4t-4 are t=2
Find the zeros of t^2=4t-4
The zeros of t^2=4t-4 are t=2