What are the solutions to the equation (x)=2x^2-7x-4 ?

The solutions to the equation (x)=2x^2-7x-4 are x=2+sqrt(6),x=2-sqrt(6)

Find the zeros of (x)=2x^2-7x-4

The zeros of (x)=2x^2-7x-4 are x=2+sqrt(6),x=2-sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x) = 2 x^{2} - 7 x - 4

x = 2 + 6, x = 2 - 6

Decimal Notation

x = 4.44948 \dots, x = - 0.44948 \dots

Solution steps

(x) = 2 x^{2} - 7 x - 4

Refine

x = 2 x^{2} - 7 x - 4

Switch sides

2 x^{2} - 7 x - 4 = x

Move

x

to the left side

2 x^{2} - 8 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 (- 4) = 46

x_{1, 2} = \frac{- ( - 8 ) \pm 4 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 6}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 4 6}{2 \cdot 2}

x = \frac{- ( - 8 ) + 4 6}{2 \cdot 2} : 2 + 6

x = \frac{- ( - 8 ) - 4 6}{2 \cdot 2} : 2 - 6

The solutions to the quadratic equation are:

x = 2 + 6, x = 2 - 6

3 y^{2} + 16 y + 5 = 0

2 x^{2} - 8 = - 8

x, 2 x^{2} + m x + 8 = 0

x^{2} - 31 x = 0

3 y^{2} + 3 y = 0

What are the solutions to the equation (x)=2x^2-7x-4 ?
The solutions to the equation (x)=2x^2-7x-4 are x=2+sqrt(6),x=2-sqrt(6)
Find the zeros of (x)=2x^2-7x-4
The zeros of (x)=2x^2-7x-4 are x=2+sqrt(6),x=2-sqrt(6)