What are the solutions to the equation 2x^2-8=-8 ?

The solutions to the equation 2x^2-8=-8 are x=0

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2x^2-8=-8

2 x^{2} - 8 = - 8

x = 0

Solution steps

2 x^{2} - 8 = - 8

Move

8

to the right side

2 x^{2} = 0

Divide both sides by

2

x = 0

x, 2 x^{2} + m x + 8 = 0

x^{2} - 31 x = 0

3 y^{2} + 3 y = 0

(4 - x) (- 5 - x) + 18 = 0

3 x^{2} - 5 (x - 4) = 15

What are the solutions to the equation 2x^2-8=-8 ?
The solutions to the equation 2x^2-8=-8 are x=0
Find the zeros of 2x^2-8=-8
The zeros of 2x^2-8=-8 are x=0