What are the solutions to the equation 3x^2-5(x-4)=15 ?

The solutions to the equation 3x^2-5(x-4)=15 are x= 5/6+i(sqrt(35))/6 ,x= 5/6-i(sqrt(35))/6

Find the zeros of 3x^2-5(x-4)=15

The zeros of 3x^2-5(x-4)=15 are x= 5/6+i(sqrt(35))/6 ,x= 5/6-i(sqrt(35))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 5 (x - 4) = 15

x = \frac{5}{6} + i \frac{35}{6}, x = \frac{5}{6} - i \frac{35}{6}

Solution steps

3 x^{2} - 5 (x - 4) = 15

Expand

3 x^{2} - 5 (x - 4) : 3 x^{2} - 5 x + 20

3 x^{2} - 5 x + 20 = 15

Move

15

to the left side

3 x^{2} - 5 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

(- 5)^{2} - 4 \cdot 3 \cdot 5 : 35 i

x_{1, 2} = \frac{- ( - 5 ) \pm 35 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 35 i}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 35 i}{2 \cdot 3}

x = \frac{- ( - 5 ) + 35 i}{2 \cdot 3} : \frac{5}{6} + i \frac{35}{6}

x = \frac{- ( - 5 ) - 35 i}{2 \cdot 3} : \frac{5}{6} - i \frac{35}{6}

The solutions to the quadratic equation are:

x = \frac{5}{6} + i \frac{35}{6}, x = \frac{5}{6} - i \frac{35}{6}

x^{2} = x - \frac{1}{4}

2 x (x + 1) = 5 x - 1

x, f = (4 + k) x^{2} - 3 x + 6

\frac{70 - 2 x ^{2}}{4} = 5

\frac{( x - 1 ) ^{2}}{3} = 3

What are the solutions to the equation 3x^2-5(x-4)=15 ?
The solutions to the equation 3x^2-5(x-4)=15 are x= 5/6+i(sqrt(35))/6 ,x= 5/6-i(sqrt(35))/6
Find the zeros of 3x^2-5(x-4)=15
The zeros of 3x^2-5(x-4)=15 are x= 5/6+i(sqrt(35))/6 ,x= 5/6-i(sqrt(35))/6