What are the solutions to the equation 2x(x+1)=5x-1 ?

The solutions to the equation 2x(x+1)=5x-1 are x=1,x= 1/2

Find the zeros of 2x(x+1)=5x-1

The zeros of 2x(x+1)=5x-1 are x=1,x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x (x + 1) = 5 x - 1

x = 1, x = \frac{1}{2}

Decimal Notation

x = 1, x = 0.5

Solution steps

2 x (x + 1) = 5 x - 1

Expand

2 x (x + 1) : 2 x^{2} + 2 x

2 x^{2} + 2 x = 5 x - 1

Move

1

to the left side

2 x^{2} + 2 x + 1 = 5 x

Move

5 x

to the left side

2 x^{2} - 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 \cdot 1 = 1

x_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 2}

x = \frac{- ( - 3 ) + 1}{2 \cdot 2} : 1

x = \frac{- ( - 3 ) - 1}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{2}

x, f = (4 + k) x^{2} - 3 x + 6

\frac{70 - 2 x ^{2}}{4} = 5

\frac{( x - 1 ) ^{2}}{3} = 3

\frac{( x - 1 ) ^{2}}{3} = 7

x, x^{2} - 2 x = z^{2} - 2 z

What are the solutions to the equation 2x(x+1)=5x-1 ?
The solutions to the equation 2x(x+1)=5x-1 are x=1,x= 1/2
Find the zeros of 2x(x+1)=5x-1
The zeros of 2x(x+1)=5x-1 are x=1,x= 1/2