What are the solutions to the equation 2x(-3x-4)=-6x ?

The solutions to the equation 2x(-3x-4)=-6x are x=0,x=-1/3

Find the zeros of 2x(-3x-4)=-6x

The zeros of 2x(-3x-4)=-6x are x=0,x=-1/3

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2 x (- 3 x - 4) = - 6 x

x = 0, x = - \frac{1}{3}

Decimal Notation

x = 0, x = - 0.33333 \dots

Solution steps

2 x (- 3 x - 4) = - 6 x

Move

6 x

to the left side

2 x (- 3 x - 4) + 6 x = 0

Factor

2 x (- 3 x - 4) + 6 x : 2 x (- 3 x - 1)

2 x (- 3 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or - 3 x - 1 = 0

Solve

- 3 x - 1 = 0 : x = - \frac{1}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{3}

x (x + 4) = 12

(4 x + 11) (2 x - 8) = x (2 x + 7)

- 3 x^{2} - 18 x - 12 = 0

\frac{1}{2} x^{2} = 1

\frac{1}{2} x^{2} = 2

What are the solutions to the equation 2x(-3x-4)=-6x ?
The solutions to the equation 2x(-3x-4)=-6x are x=0,x=-1/3
Find the zeros of 2x(-3x-4)=-6x
The zeros of 2x(-3x-4)=-6x are x=0,x=-1/3