What are the solutions to the equation 4-x^2+3x=0 ?

The solutions to the equation 4-x^2+3x=0 are x=-1,x=4

Find the zeros of 4-x^2+3x=0

The zeros of 4-x^2+3x=0 are x=-1,x=4

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4 - x^{2} + 3 x = 0

x = - 1, x = 4

Solution steps

4 - x^{2} + 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 3 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 4 = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 ( - 1 )}, x_{2} = \frac{- 3 - 5}{2 ( - 1 )}

x = \frac{- 3 + 5}{2 ( - 1 )} : - 1

x = \frac{- 3 - 5}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = - 1, x = 4

12 x^{2} + 144 = 640

x^{2} + 40 x + 200 = 0

5 x = 14 - x^{2}

a^{2} + 7 a + 6 = 0

y, y^{2} + y = t + c

What are the solutions to the equation 4-x^2+3x=0 ?
The solutions to the equation 4-x^2+3x=0 are x=-1,x=4
Find the zeros of 4-x^2+3x=0
The zeros of 4-x^2+3x=0 are x=-1,x=4