What are the solutions to the equation x^2+40x+200=0 ?

The solutions to the equation x^2+40x+200=0 are x=10(sqrt(2)-2),x=-10(2+sqrt(2))

Find the zeros of x^2+40x+200=0

The zeros of x^2+40x+200=0 are x=10(sqrt(2)-2),x=-10(2+sqrt(2))

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x^{2} + 40 x + 200 = 0

x = 10 (2 - 2), x = - 10 (2 + 2)

Decimal Notation

x = - 5.85786 \dots, x = - 34.14213 \dots

Solution steps

x^{2} + 40 x + 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 1 \cdot 200}{2 \cdot 1}

4 0^{2} - 4 \cdot 1 \cdot 200 = 202

x_{1, 2} = \frac{- 40 \pm 20 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 40 + 20 2}{2 \cdot 1}, x_{2} = \frac{- 40 - 20 2}{2 \cdot 1}

x = \frac{- 40 + 20 2}{2 \cdot 1} : 10 (2 - 2)

x = \frac{- 40 - 20 2}{2 \cdot 1} : - 10 (2 + 2)

The solutions to the quadratic equation are:

x = 10 (2 - 2), x = - 10 (2 + 2)

5 x = 14 - x^{2}

a^{2} + 7 a + 6 = 0

y, y^{2} + y = t + c

(x - 1) (2 x - 1) = 0

- x^{2} - 7 x + 5 = 0

What are the solutions to the equation x^2+40x+200=0 ?
The solutions to the equation x^2+40x+200=0 are x=10(sqrt(2)-2),x=-10(2+sqrt(2))
Find the zeros of x^2+40x+200=0
The zeros of x^2+40x+200=0 are x=10(sqrt(2)-2),x=-10(2+sqrt(2))