What are the solutions to the equation (x-1)(2x-1)=0 ?

The solutions to the equation (x-1)(2x-1)=0 are x=1,x= 1/2

Find the zeros of (x-1)(2x-1)=0

The zeros of (x-1)(2x-1)=0 are x=1,x= 1/2

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(x - 1) (2 x - 1) = 0

x = 1, x = \frac{1}{2}

Decimal Notation

x = 1, x = 0.5

Solution steps

(x - 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x - 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{2}

- x^{2} - 7 x + 5 = 0

6 x^{2} + 7 = 3 x^{2} + 250

2 x^{2} - 8 x + 80 = 2 (x + 10)

x^{2} + 1 = 0, e x^{2} - 1 = 0

6 x^{2} + x = 2

What are the solutions to the equation (x-1)(2x-1)=0 ?
The solutions to the equation (x-1)(2x-1)=0 are x=1,x= 1/2
Find the zeros of (x-1)(2x-1)=0
The zeros of (x-1)(2x-1)=0 are x=1,x= 1/2