What are the solutions to the equation 6x^2+7x-49=0 ?

The solutions to the equation 6x^2+7x-49=0 are x= 7/3 ,x=-7/2

Find the zeros of 6x^2+7x-49=0

The zeros of 6x^2+7x-49=0 are x= 7/3 ,x=-7/2

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6 x^{2} + 7 x - 49 = 0

x = \frac{7}{3}, x = - \frac{7}{2}

Decimal Notation

x = 2.33333 \dots, x = - 3.5

Solution steps

6 x^{2} + 7 x - 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 ( - 49 )}{2 \cdot 6}

7^{2} - 4 \cdot 6 (- 49) = 35

x_{1, 2} = \frac{- 7 \pm 35}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 7 + 35}{2 \cdot 6}, x_{2} = \frac{- 7 - 35}{2 \cdot 6}

x = \frac{- 7 + 35}{2 \cdot 6} : \frac{7}{3}

x = \frac{- 7 - 35}{2 \cdot 6} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - \frac{7}{2}

3 x^{2} + 4 x - 68100 = 0

0 = - x^{2} + 3 x - 2

- 3 x^{2} + 12 x

x, f (x + h) = 10 + 3 x^{2}

x^{2} - 8 x - 38 = 0

What are the solutions to the equation 6x^2+7x-49=0 ?
The solutions to the equation 6x^2+7x-49=0 are x= 7/3 ,x=-7/2
Find the zeros of 6x^2+7x-49=0
The zeros of 6x^2+7x-49=0 are x= 7/3 ,x=-7/2