What are the solutions to the equation 2k^2-3k-5=0 ?

The solutions to the equation 2k^2-3k-5=0 are k= 5/2 ,k=-1

Find the zeros of 2k^2-3k-5=0

The zeros of 2k^2-3k-5=0 are k= 5/2 ,k=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 k^{2} - 3 k - 5 = 0

k = \frac{5}{2}, k = - 1

Decimal Notation

k = 2.5, k = - 1

Solution steps

2 k^{2} - 3 k - 5 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 5) = 7

k_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 2}, k_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 2}

k = \frac{- ( - 3 ) + 7}{2 \cdot 2} : \frac{5}{2}

k = \frac{- ( - 3 ) - 7}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

k = \frac{5}{2}, k = - 1

x^{2} + 2 0^{2} = (36 - 10)^{2}

x^{2} - 4 x = 3

x^{2} - 4 x = 9

x^{2} - (a + b) x + a \cdot b = 0

2 x^{2} - 40 x = 0

What are the solutions to the equation 2k^2-3k-5=0 ?
The solutions to the equation 2k^2-3k-5=0 are k= 5/2 ,k=-1
Find the zeros of 2k^2-3k-5=0
The zeros of 2k^2-3k-5=0 are k= 5/2 ,k=-1