What are the solutions to the equation x^2-(a+b)x+a*b=0 ?

The solutions to the equation x^2-(a+b)x+a*b=0 are x=a,x=b

Find the zeros of x^2-(a+b)x+a*b=0

The zeros of x^2-(a+b)x+a*b=0 are x=a,x=b

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - (a + b) x + a \cdot b = 0

x = a, x = b

Solution steps

x^{2} - (a + b) x + ab = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - a - b ) \pm ( - a - b ) ^{2} - 4 \cdot 1 \cdot ab}{2 \cdot 1}

Simplify

(- a - b)^{2} - 4 \cdot 1 \cdot ab : a - b

x_{1, 2} = \frac{- ( - a - b ) \pm ( a - b )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - a - b ) + a - b}{2 \cdot 1}, x_{2} = \frac{- ( - a - b ) - ( a - b )}{2 \cdot 1}

x = \frac{- ( - a - b ) + a - b}{2 \cdot 1} : a

x = \frac{- ( - a - b ) - ( a - b )}{2 \cdot 1} : b

The solutions to the quadratic equation are:

x = a, x = b

2 x^{2} - 40 x = 0

x (x + 6) + 4 = 0

x^{2} + 16 x - 14 = 0

4 x^{2} + 9 x = - 5

4 x^{2} + 9 x = - 2

What are the solutions to the equation x^2-(a+b)x+a*b=0 ?
The solutions to the equation x^2-(a+b)x+a*b=0 are x=a,x=b
Find the zeros of x^2-(a+b)x+a*b=0
The zeros of x^2-(a+b)x+a*b=0 are x=a,x=b