What are the solutions to the equation 4x^2+9x=-5 ?

The solutions to the equation 4x^2+9x=-5 are x=-1,x=-5/4

Find the zeros of 4x^2+9x=-5

The zeros of 4x^2+9x=-5 are x=-1,x=-5/4

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4 x^{2} + 9 x = - 5

x = - 1, x = - \frac{5}{4}

Decimal Notation

x = - 1, x = - 1.25

Solution steps

4 x^{2} + 9 x = - 5

Move

5

to the left side

4 x^{2} + 9 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

9^{2} - 4 \cdot 4 \cdot 5 = 1

x_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 9 + 1}{2 \cdot 4}, x_{2} = \frac{- 9 - 1}{2 \cdot 4}

x = \frac{- 9 + 1}{2 \cdot 4} : - 1

x = \frac{- 9 - 1}{2 \cdot 4} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{5}{4}

4 x^{2} + 9 x = - 2

a, (a - b) (a + b) = b (a - b)

y, - 2 x^{2} y + y^{2} = 1

7 x^{2} - 11 x + 3 = 0

4 = a^{2} + 3 a

What are the solutions to the equation 4x^2+9x=-5 ?
The solutions to the equation 4x^2+9x=-5 are x=-1,x=-5/4
Find the zeros of 4x^2+9x=-5
The zeros of 4x^2+9x=-5 are x=-1,x=-5/4