What are the solutions to the equation 4x^2+9x=-2 ?

The solutions to the equation 4x^2+9x=-2 are x=-1/4 ,x=-2

Find the zeros of 4x^2+9x=-2

The zeros of 4x^2+9x=-2 are x=-1/4 ,x=-2

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4 x^{2} + 9 x = - 2

x = - \frac{1}{4}, x = - 2

Decimal Notation

x = - 0.25, x = - 2

Solution steps

4 x^{2} + 9 x = - 2

Move

2

to the left side

4 x^{2} + 9 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

9^{2} - 4 \cdot 4 \cdot 2 = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 9 + 7}{2 \cdot 4}, x_{2} = \frac{- 9 - 7}{2 \cdot 4}

x = \frac{- 9 + 7}{2 \cdot 4} : - \frac{1}{4}

x = \frac{- 9 - 7}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - 2

a, (a - b) (a + b) = b (a - b)

y, - 2 x^{2} y + y^{2} = 1

7 x^{2} - 11 x + 3 = 0

4 = a^{2} + 3 a

x^{2} = 2 5^{2} + 7^{2}

What are the solutions to the equation 4x^2+9x=-2 ?
The solutions to the equation 4x^2+9x=-2 are x=-1/4 ,x=-2
Find the zeros of 4x^2+9x=-2
The zeros of 4x^2+9x=-2 are x=-1/4 ,x=-2