What are the solutions to the equation 2x^2+4x+15=175 ?

The solutions to the equation 2x^2+4x+15=175 are x=8,x=-10

Find the zeros of 2x^2+4x+15=175

The zeros of 2x^2+4x+15=175 are x=8,x=-10

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2 x^{2} + 4 x + 15 = 175

x = 8, x = - 10

Solution steps

2 x^{2} + 4 x + 15 = 175

Move

175

to the left side

2 x^{2} + 4 x - 160 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 160 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 160) = 36

x_{1, 2} = \frac{- 4 \pm 36}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 36}{2 \cdot 2}, x_{2} = \frac{- 4 - 36}{2 \cdot 2}

x = \frac{- 4 + 36}{2 \cdot 2} : 8

x = \frac{- 4 - 36}{2 \cdot 2} : - 10

The solutions to the quadratic equation are:

x = 8, x = - 10

5 x^{2} - x + 5 = 0

x^{2} - 14 x = 51

167 = 4 π r^{2}

(x + 2)^{2} = - 36

7 x^{2} + 43 d + 6 = 0

What are the solutions to the equation 2x^2+4x+15=175 ?
The solutions to the equation 2x^2+4x+15=175 are x=8,x=-10
Find the zeros of 2x^2+4x+15=175
The zeros of 2x^2+4x+15=175 are x=8,x=-10