What are the solutions to the equation 167=4pir^2 ?

The solutions to the equation 167=4pir^2 are r=(sqrt(167))/(2sqrt(pi)),r=-(sqrt(167))/(2sqrt(pi))

Find the zeros of 167=4pir^2

The zeros of 167=4pir^2 are r=(sqrt(167))/(2sqrt(pi)),r=-(sqrt(167))/(2sqrt(pi))

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167 = 4 π r^{2}

r = \frac{167}{2 π}, r = - \frac{167}{2 π}

Decimal Notation

r = 3.64546 \dots, r = - 3.64546 \dots

Solution steps

167 = 4 π r^{2}

Switch sides

4 π r^{2} = 167

Divide both sides by

4 π

r^{2} = \frac{167}{4 π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{167}{4 π}, r = - \frac{167}{4 π}

\frac{167}{4 π} = \frac{167}{2 π}

- \frac{167}{4 π} = - \frac{167}{2 π}

r = \frac{167}{2 π}, r = - \frac{167}{2 π}

(x + 2)^{2} = - 36

7 x^{2} + 43 d + 6 = 0

7 x^{2} + 20 x - 3 = 0

5 x^{2} - x + 7 = 0

0 = y^{2} + 1

What are the solutions to the equation 167=4pir^2 ?
The solutions to the equation 167=4pir^2 are r=(sqrt(167))/(2sqrt(pi)),r=-(sqrt(167))/(2sqrt(pi))
Find the zeros of 167=4pir^2
The zeros of 167=4pir^2 are r=(sqrt(167))/(2sqrt(pi)),r=-(sqrt(167))/(2sqrt(pi))