What are the solutions to the equation 0=y^2+1 ?

The solutions to the equation 0=y^2+1 are y=i,y=-i

Find the zeros of 0=y^2+1

The zeros of 0=y^2+1 are y=i,y=-i

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0 = y^{2} + 1

y = i, y = - i

Solution steps

0 = y^{2} + 1

Switch sides

y^{2} + 1 = 0

Move

1

to the right side

y^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 1, y = - - 1

- 1 = i

- - 1 = - i

y = i, y = - i

- 4 x^{2} = 48 x + 128

4 w^{2} = 4 w + 3

x^{2} + 12 x - 69

3 x^{2} = 12 x^{2} - 144

3 (y + 1)^{2} - 10 (y + 1) + 8 = 0

What are the solutions to the equation 0=y^2+1 ?
The solutions to the equation 0=y^2+1 are y=i,y=-i
Find the zeros of 0=y^2+1
The zeros of 0=y^2+1 are y=i,y=-i