What are the solutions to the equation 3(y+1)^2-10(y+1)+8=0 ?

The solutions to the equation 3(y+1)^2-10(y+1)+8=0 are y=1,y= 1/3

Find the zeros of 3(y+1)^2-10(y+1)+8=0

The zeros of 3(y+1)^2-10(y+1)+8=0 are y=1,y= 1/3

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3 (y + 1)^{2} - 10 (y + 1) + 8 = 0

y = 1, y = \frac{1}{3}

Decimal Notation

y = 1, y = 0.33333 \dots

Solution steps

3 (y + 1)^{2} - 10 (y + 1) + 8 = 0

Expand

3 (y + 1)^{2} - 10 (y + 1) + 8 : 3 y^{2} - 4 y + 1

3 y^{2} - 4 y + 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 \cdot 1 = 2

y_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 3}, y_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 3}

y = \frac{- ( - 4 ) + 2}{2 \cdot 3} : 1

y = \frac{- ( - 4 ) - 2}{2 \cdot 3} : \frac{1}{3}

The solutions to the quadratic equation are:

y = 1, y = \frac{1}{3}

3 w^{2} + 49 w + 60 = 0

d (x) = 5 x^{2} + 3 x - 4, d (2 x - 3)

x^{2} + 8 x - 7

- 3 x^{2} + 3 x - 1 = 0

- 2 x^{2} + 11 x - 12 = 0

What are the solutions to the equation 3(y+1)^2-10(y+1)+8=0 ?
The solutions to the equation 3(y+1)^2-10(y+1)+8=0 are y=1,y= 1/3
Find the zeros of 3(y+1)^2-10(y+1)+8=0
The zeros of 3(y+1)^2-10(y+1)+8=0 are y=1,y= 1/3