What are the solutions to the equation 3w^2+49w+60=0 ?

The solutions to the equation 3w^2+49w+60=0 are w=-4/3 ,w=-15

Find the zeros of 3w^2+49w+60=0

The zeros of 3w^2+49w+60=0 are w=-4/3 ,w=-15

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3 w^{2} + 49 w + 60 = 0

w = - \frac{4}{3}, w = - 15

Decimal Notation

w = - 1.33333 \dots, w = - 15

Solution steps

3 w^{2} + 49 w + 60 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 49 \pm 4 9 ^{2} - 4 \cdot 3 \cdot 60}{2 \cdot 3}

4 9^{2} - 4 \cdot 3 \cdot 60 = 41

w_{1, 2} = \frac{- 49 \pm 41}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- 49 + 41}{2 \cdot 3}, w_{2} = \frac{- 49 - 41}{2 \cdot 3}

w = \frac{- 49 + 41}{2 \cdot 3} : - \frac{4}{3}

w = \frac{- 49 - 41}{2 \cdot 3} : - 15

The solutions to the quadratic equation are:

w = - \frac{4}{3}, w = - 15

d (x) = 5 x^{2} + 3 x - 4, d (2 x - 3)

x^{2} + 8 x - 7

- 3 x^{2} + 3 x - 1 = 0

- 2 x^{2} + 11 x - 12 = 0

v w^{2} + y = x, w

What are the solutions to the equation 3w^2+49w+60=0 ?
The solutions to the equation 3w^2+49w+60=0 are w=-4/3 ,w=-15
Find the zeros of 3w^2+49w+60=0
The zeros of 3w^2+49w+60=0 are w=-4/3 ,w=-15