What are the solutions to the equation 3x(2x+5)=-7 ?

The solutions to the equation 3x(2x+5)=-7 are x=(-15+sqrt(57))/(12),x=(-15-sqrt(57))/(12)

Find the zeros of 3x(2x+5)=-7

The zeros of 3x(2x+5)=-7 are x=(-15+sqrt(57))/(12),x=(-15-sqrt(57))/(12)

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3 x (2 x + 5) = - 7

x = \frac{- 15 + 57}{12}, x = \frac{- 15 - 57}{12}

Decimal Notation

x = - 0.62084 \dots, x = - 1.87915 \dots

Solution steps

3 x (2 x + 5) = - 7

Expand

3 x (2 x + 5) : 6 x^{2} + 15 x

6 x^{2} + 15 x = - 7

Move

7

to the left side

6 x^{2} + 15 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 6 \cdot 7}{2 \cdot 6}

1 5^{2} - 4 \cdot 6 \cdot 7 = 57

x_{1, 2} = \frac{- 15 \pm 57}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 15 + 57}{2 \cdot 6}, x_{2} = \frac{- 15 - 57}{2 \cdot 6}

x = \frac{- 15 + 57}{2 \cdot 6} : \frac{- 15 + 57}{12}

x = \frac{- 15 - 57}{2 \cdot 6} : \frac{- 15 - 57}{12}

The solutions to the quadratic equation are:

x = \frac{- 15 + 57}{12}, x = \frac{- 15 - 57}{12}

36 y^{2} - 81 = 0

2 x (x - 2) = 4 x^{2} - 5 x

xx + 3 x + 2 = 0

12 a^{2} - 4 a - 13 = 5 a + 8

x, (2 x + 3) (x + 4) = 1

What are the solutions to the equation 3x(2x+5)=-7 ?
The solutions to the equation 3x(2x+5)=-7 are x=(-15+sqrt(57))/(12),x=(-15-sqrt(57))/(12)
Find the zeros of 3x(2x+5)=-7
The zeros of 3x(2x+5)=-7 are x=(-15+sqrt(57))/(12),x=(-15-sqrt(57))/(12)