What are the solutions to the equation x^2+4-4x=0 ?

The solutions to the equation x^2+4-4x=0 are x=2

Find the zeros of x^2+4-4x=0

The zeros of x^2+4-4x=0 are x=2

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x^{2} + 4 - 4 x = 0

x = 2

Solution steps

x^{2} + 4 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

2 m^{2} - 10 = 36

5 (14 + 5) = s^{2} - 7^{2}

t, d = \frac{g t ^{2}}{2}

2 x^{2} = 5 x + 6

1.24 a^{2} + 47.5 a - 1917.81 = 0

What are the solutions to the equation x^2+4-4x=0 ?
The solutions to the equation x^2+4-4x=0 are x=2
Find the zeros of x^2+4-4x=0
The zeros of x^2+4-4x=0 are x=2