What are the solutions to the equation 3y^2+6y+9=0 ?

The solutions to the equation 3y^2+6y+9=0 are y=-1+sqrt(2)i,y=-1-sqrt(2)i

Find the zeros of 3y^2+6y+9=0

The zeros of 3y^2+6y+9=0 are y=-1+sqrt(2)i,y=-1-sqrt(2)i

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3 y^{2} + 6 y + 9 = 0

y = - 1 + 2 i, y = - 1 - 2 i

Solution steps

3 y^{2} + 6 y + 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

Simplify

6^{2} - 4 \cdot 3 \cdot 9 : 62 i

y_{1, 2} = \frac{- 6 \pm 6 2 i}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- 6 + 6 2 i}{2 \cdot 3}, y_{2} = \frac{- 6 - 6 2 i}{2 \cdot 3}

y = \frac{- 6 + 6 2 i}{2 \cdot 3} : - 1 + 2 i

y = \frac{- 6 - 6 2 i}{2 \cdot 3} : - 1 - 2 i

The solutions to the quadratic equation are:

y = - 1 + 2 i, y = - 1 - 2 i

x (x + 5) = 3 x - 16 (x + 5)

2 (x - 3)^{2} - 6 = - 4

3 x^{2} + 3 x + 15 = 0

0 = x (x + 5)

x^{2} - 4 x = 32

What are the solutions to the equation 3y^2+6y+9=0 ?
The solutions to the equation 3y^2+6y+9=0 are y=-1+sqrt(2)i,y=-1-sqrt(2)i
Find the zeros of 3y^2+6y+9=0
The zeros of 3y^2+6y+9=0 are y=-1+sqrt(2)i,y=-1-sqrt(2)i