What are the solutions to the equation 12x^2-58x-10=0 ?

The solutions to the equation 12x^2-58x-10=0 are x=5,x=-1/6

Find the zeros of 12x^2-58x-10=0

The zeros of 12x^2-58x-10=0 are x=5,x=-1/6

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12 x^{2} - 58 x - 10 = 0

x = 5, x = - \frac{1}{6}

Decimal Notation

x = 5, x = - 0.16666 \dots

Solution steps

12 x^{2} - 58 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 58 ) \pm ( - 58 ) ^{2} - 4 \cdot 12 ( - 10 )}{2 \cdot 12}

(- 58)^{2} - 4 \cdot 12 (- 10) = 62

x_{1, 2} = \frac{- ( - 58 ) \pm 62}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 58 ) + 62}{2 \cdot 12}, x_{2} = \frac{- ( - 58 ) - 62}{2 \cdot 12}

x = \frac{- ( - 58 ) + 62}{2 \cdot 12} : 5

x = \frac{- ( - 58 ) - 62}{2 \cdot 12} : - \frac{1}{6}

The solutions to the quadratic equation are:

x = 5, x = - \frac{1}{6}

- 16 t^{2} + 296 = 0

3 (w + 5)^{2} = 27

2 d (d - 6) = 0

x (x + 7) - 3 x = 0

0 = 2 x^{2} + 5 x

What are the solutions to the equation 12x^2-58x-10=0 ?
The solutions to the equation 12x^2-58x-10=0 are x=5,x=-1/6
Find the zeros of 12x^2-58x-10=0
The zeros of 12x^2-58x-10=0 are x=5,x=-1/6